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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMEasy2 minPYQ_2015

PhysicsEasysingle choice

Three blocks A, B and C, of masses $4 kg, 2 kg$ $1 kg$ and respectively, are in contact on a frictionless surface, as shown. If a force of $14 N$ is applied on the $4 kg$ block, then the contact force between A and B is:

NEET 2015 (Phase 1)

Options:

Answer:

Solution:

$F = M a = (M_{a} + M_{b} + M_{c}) a 14 = (4 + 2 + 1) a = 7 a a = 2$ Let $F^{'}$ be the contact force between $A & B$ , $F - F^{'} = 4 a 14 - F^{'} = 4 a = 4 \times 2 F^{'} = 6 N$

Stream:NEETSubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: PYQ_2015

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