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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMMedium2 minPYQ_2015

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A block of mass 2 kg is pushed against a rough vertical wall with a force of 40 N , coefficient of static friction being 0.5. Another horizontal force of 15 N , is applied on the block in a direction parallel to the wall. If the block will move, then its direction would be

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Solution:

The net force $= 2 0^{2} + 1 5^{2} - 0.5 \times 40$ $= 25 - 20 = 5 N ∴ tan θ = \frac{20}{15} = \frac{4}{3} ∴ θ = tan^{- 1} (\frac{4}{3}) = 5 3^{\circ}$ So, the block will move at an angle $5 3^{\circ}$ with the 15 N force.

Stream:JIPMERSubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: PYQ_2015

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