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PhysicsNLMFrictionEasy2 minPYQ_2003

PhysicsEasysingle choice

A marble block of mass $2 kg$ lying on ice when given a velocity of $6 m / s$ is stopped by friction in $10 s$ . Then the coefficient of friction is

Answer:

Solution:

$a = μg = \frac{6}{10}$ [ using $v = u + at$ ] $\Rightarrow μ = \frac{6}{10 \times g} = \frac{6}{10 \times 10} = 0.06$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: PYQ_2003

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