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PhysicsModern PhysicsX-raysEasy2 minQB

PhysicsEasysingle choice

The potential difference applied to an X-ray tube is increased. As a result, in the emitted radiation :

Answer:

Solution:

$e V = \frac{h c}{λ} \Rightarrow V = \frac{12400}{λ ( in A ˚ )}$ Increasing $V$ decreases $λ_{min}$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:X-rays

⏱ 2mℹ️ Source: QB

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