Hydrogen atoms in the ground state are excited by monochromatic radiation of wavelength 975 A ˚ . The number of lines in the resulting spectrum will be:

E = 12400/975 = 12.72 eV ≈ 13.6 ( 1 − 16 1 ) , so atoms reach n = 4 . Lines = 4 C 2 = 6 .

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Hydrogen atoms in the ground state are excited by monochromatic radiation of wavelength $975 \overset{˚}{A}$ . The number of lines in the resulting spectrum will be:

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Answer:

Solution:

$E = 12400/975 = 12.72 eV \approx 13.6 (1 - \frac{1}{16})$ , so atoms reach $n = 4$ . Lines $=^{4} C_{2} = 6$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

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