Physics - Modern Physics Question with Solution | TestHub

For Lyman series:

For first member, $\frac{1}{\lambda }=\frac{13.6Z^2}{hc}\left[\frac{1}{1^2}-\frac{1}{2^2}\right]$ ….. (i)

For second member, $\frac{1}{{\lambda }^{\prime }}=\frac{13.6Z^2}{hc}\left[\frac{1}{1^2}-\frac{1}{3^2}\right]$ ….. (ii) On dividing (i) and (ii), we get

${\lambda }^{\prime }=\frac{27}{32}\lambda$