Physics - Modern Physics Question with Solution | TestHub

The circuit shown is placed in vacuum. Both the capacitors are identical and they have the same capacitance C.

Light is incident on the left plate of the upper capacitor. When all the switches are open then the $hf$ versus ${\mathrm{KE}}_{\max }$ is shown by the straight line (1). In all the cases, we are measuring the ${\mathrm{KE}}_{\max }$ when the electron reaches the opposite plate. When only ${\mathrm{S}}_1$ and ${\mathrm{S}}_2$ are closed, the graph becomes (2).

When only ${\mathrm{S}}_3$ and ${\mathrm{S}}_4$ are closed then the graph becomes (3).