In a photoelectric effect measurement the stopping potential for a given metal is found to be V 0 Volts when radiation of wavelength λ 0 is used. If radiation of wavelength 2 λ 0 is used with sa

Question

In a photoelectric effect measurement the stopping potential for a given metal is found to be $V_{0}$ Volts when radiation of wavelength $λ_{0}$ is used. If radiation of wavelength $2 λ_{0}$ is used with same metal, then the stopping potential will be observed to be (Where symbols have their usual meaning)

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Answer:

D

Solution:

$e V_{0} = \frac{h c}{λ _{0}} - ϕ e V_{0}^{'} = \frac{h c}{2 λ _{0}} - ϕ V_{0}^{'} = V_{0} - \frac{h c}{2 e λ _{0}}$

provided emission still occurs

TestHub · Accepted Answer

​ e V 0 ​ = λ 0 ​ h c ​ − ϕ ​ e V 0 ′ ​ = 2 λ 0 ​ h c ​ − ϕ ​ V 0 ′ ​ = V 0 ​ − 2 e λ 0 ​ h c ​ ​ provided emission still occurs

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