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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureMedium2 minQB

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Radiation coming from transitions $n = 2$ to $n = 1$ of hydrogen atoms fall on $(He)^{+}$ ions in $n = 1$ and $n = 2$ states. The possible transition of helium ions as they absorb energy from the radiation is:

Options:

Answer:

Solution:

$E = 13.6 (\frac{1}{1 ^{1}} - \frac{1}{2 ^{2}}) e V ... (1)$ For Helium:

$E = 13.6 (2)^{2} (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}) e V ... (2)$

From equation $(1)$ and $(2)$

$13.6 (\frac{3}{4}) = 13.6 (4) (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$

$\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}} = \frac{3}{16}$

From option, $n_{1} = 2$ and $n_{2} = 4$ are satisfying the equation.

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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