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PhysicsModern PhysicsX-raysMedium2 minQB

PhysicsMediumsingle choice

The $K_{α}$ X-ray emission line of tungsten occurs at $λ = 0.021 nm$ . The energy difference between K and L levels in this atom is about :-

Answer:

Solution:

$E = \frac{h c}{λ}$

$E = \frac{1240 eV nm}{0.021 nm}$

$E \approx 5.9 \times 1 0^{4} eV = 59 keV$

Option (C)

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:X-rays

⏱ 2mℹ️ Source: QB

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