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PhysicsModern PhysicsAtomic structureMedium2 minQB

PhysicsMediumsingle choice

The product of the speed of the electron in the first Bohr orbit of hydrogen and the speed of light is equal to (where e, h and c have their usual meaning) :-

Options:

Answer:

Solution:

Speed in first Bohr orbit: $v = \frac{e ^{2}}{2 ϵ _{0} h}$

Required product: $v c = \frac{e ^{2} c}{2 ϵ _{0} h}$

Option (C)

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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