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PhysicsModern PhysicsAtomic structureMedium2 minQB

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The radius of the shortest orbit in a one-electron system is 18 pm. It may be:

Answer:

Solution:

$r_{1} = a_{0} / Z \Rightarrow Z = 52.9/18 \approx 3$ , so the system is $Li^{+ 2}$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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