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PhysicsModern PhysicsAtomic structureEasy2 minQB

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If $13.6 eV$ energy is required to ionize the hydrogen atom, then the energy required to remove an electron from $n = 2$ is

Answer:

Solution:

$E_{n} = - \frac{13.6}{n ^{2}} \Rightarrow E_{2} = - \frac{13.6}{2 ^{2}} = 3.4 eV$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

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