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PhysicsModern PhysicsAtomic structureMedium2 minQB

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If $λ_{1}$ and $λ_{2}$ are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of $λ_{1} : λ_{2}$ is :

Options:

Answer:

Solution:

$\frac{1}{λ _{1}} = R [\frac{1}{1 ^{2}} - \frac{1}{4 ^{2}}]$

$\frac{1}{λ _{2}} = R [\frac{1}{3 ^{2}} - \frac{1}{4 ^{2}}]$

$\frac{λ _{1}}{λ _{2}} = \frac{[ \frac{1}{9} - \frac{1}{16} ]}{[ 1 - \frac{1}{16} ]} = \frac{7}{9 \times 15}$

$\frac{λ _{1}}{λ _{2}} = \frac{7}{135}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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