The K α X-ray of molybdenum has wavelength 0.071 nm . If the energy of a molybdenum atom with a K electron knocked out is 27.5 k e V , the energy of this atom when an L electron is knocked out will

Question

The K α ​ X-ray of molybdenum has wavelength 0.071 nm . If the energy of a molybdenum atom with a K electron knocked out is 27.5 k e V , the energy of this atom when an L electron is knocked out will be k e V . (Round off to the nearest integer ) [ h = 4.14 × 1 0 − 15 e V s , c = 3 × 1 0 8 ( m s ) − 1 ]

TestHub · Accepted Answer

E k α ​ ​ = E k ​ − E L ​ λ k α ​ ​ hc ​ = E k ​ − E L ​ E L ​ = E k ​ − λ k α ​ ​ h c ​ = 27.5 Ke V − 0.071 × 1 0 − 9 m 12.42 × 1 0 − 7 e Vm ​ E L ​ = ( 27.5 − 17.5 ) k e V = 10 k e V

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