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PhysicsModern PhysicsRadioactivityMedium2 minQB

PhysicsMediumsingle choice

The activity of a radioactive source at $t = 0$ was 1600 Bq and at $t = 8 sec$ it was 100 Bq. The activity observed, in Bq, at $t = 6$ seconds will be

Options:

Answer:

Solution:

1600 $\to$ 100 is 4 halvings in 8 s, so $T_{1/2} = 2$ s. At $t = 6$ s (3 half-lives):

$A = \frac{1600}{2 ^{3}} = 200 Bq$

Hence option (C).

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: QB

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