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PhysicsModern PhysicsX-raysMedium2 minQB

PhysicsMediumsingle choice

The K, L and M energy levels of platinum lie roughly at 78, 12, and 3 keV respectively. The ratio of wavelength of $K_{α}$ line to that of $K_{β}$ line in X-ray spectrum is

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Answer:

Solution:

$E_{K α} = 78 - 12 = 66 keV$

$E_{K β} = 78 - 3 = 75 keV \frac{λ _{K α}}{λ _{K β}} = \frac{E _{K β}}{E _{K α}} = \frac{75}{66} = \frac{25}{22} .$

Subject:PhysicsTopic:Modern PhysicsSubtopic:X-rays

⏱ 2mℹ️ Source: QB

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