The number of photons per second emitted by the source of monochromatic light of wavelength $600$ nm, when it delivers the power of $3.3 \times 1 0^{- 3}$ W will be
(Planck's constant $= 6.6 \times 1 0^{- 34}$ Js, $c = 3 \times 1 0^{8}$ m/s)

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Power P = λ nh c ​ where n is the number of photons emitted per second. n = h c P λ ​ Substituting the given values: n = 6.6 × 1 0 − 34 × 3 × 1 0 8 3.3 × 1 0 − 3 × 600 × 1 0 − 9 ​ n = 19.8 × 1 0 − 26 19.8 × 1 0 − 10 ​ n = 1 0 16 Answer: 1 0 16

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