In transition 'a', three α particles and two β particles are emitted in succession from the element 86 X 226 . In transition 'b', two gamma rays, one β particle and two α particl

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In transition 'a', three α particles and two β particles are emitted in succession from the element 86 ​ X 226 . In transition 'b', two gamma rays, one β particle and two α particles are emitted in succession from element 96 ​ Y 236 . The atomic number and the mass number of the new elements formed respectively are

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For transition 'a': Initial element is 86 ​ X 226 . Emission of one α particle ( 2 ​ H e 4 ) decreases the atomic number by 2 and the mass number by 4 . Emission of one β particle ( − 1 ​ e 0 ) increases the atomic number by 1 and leaves the mass number unchanged. Change in atomic number Z = − 3 ( 2 ) + 2 ( 1 ) = − 4 Change in mass number A = − 3 ( 4 ) + 2 ( 0 ) = − 12 New atomic number Z = 86 − 4 = 82 New mass number A = 226 − 12 = 214 For transition 'b': Initial element is 96 ​ Y 236 . Emission of γ rays does not change the atomic number or the mass number. Change in atomic number Z = − 2 ( 2 ) + 1 ( 1 ) = − 3 Change in mass number A = − 2 ( 4 ) + 1 ( 0 ) = − 8 New atomic number Z = 96 − 3 = 93 New mass number A = 236 − 8 = 228 Answer: a) for first transition:- atomic number = 82 , mass number = 214 b) for the second transition:- atomic number = 93 , mass number = 228

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