Physics - Modern Physics Question with Solution | TestHub

The de-Broglie wavelength of a particle is given by $\lambda =\frac{h}{p}$, where $h$ is Planck's constant and $p$ is the momentum of the particle.

Given that both particles A and B have the same de-Broglie wavelength, their momenta must be equal, so $p_A=p_B$.

The kinetic energy of a particle is given by $K=\frac{p^2}{2m}$.

Since $p_A=p_B$ and $m_1>m_2$, the kinetic energy of A is less than the kinetic energy of B ($K_A<K_B$).

Thus, their momenta are the same.

Answer: their momenta are the same