In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stopping potential is 2 V , what is the w

Question

In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stopping potential is 2 V , what is the wavelength of the em-wave ?
(Given hc $= 1242 eVnm$ where h is the Planck's constant and c is the speed of light in vaccum.)

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Answer:

A

Solution:

$ϕ = 2.14 V_{S} = 2 V$
Using photoelectric equation.
$\frac{h c}{λ} = 2.14 + 2 = 4.14 eV λ = \frac{1242}{4.14} = 300 nm$

TestHub · Accepted Answer

​ ϕ = 2.14 V S ​ = 2 V ​ Using photoelectric equation. ​ λ h c ​ = 2.14 + 2 = 4.14 eV λ = 4.14 1242 ​ = 300 nm ​

Physics - Modern Physics Question with Solution | TestHub

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