Physics - Modern Physics Question with Solution | TestHub

In the first step, ${}_z{X}^A\to {}_{z+1}{Y}^A$, the atomic number increases by $1$ and the mass number remains unchanged. This indicates the emission of a $\beta$ particle.

In the second step, ${}_{z+1}{Y}^A\to {}_{z-1}{K}^{A-4}$, the atomic number decreases by $2$ and the mass number decreases by $4$. This indicates the emission of an $\alpha$ particle.

In the third step, ${}_{z-1}{K}^{A-4}\to {}_{z-1}{K}^{A-4}$, both the atomic number and the mass number remain unchanged. This indicates the emission of a $\gamma$ ray.

The sequence of emitted radioactive radiations is $\beta ,\alpha ,\gamma$.

Answer: $\beta ,\alpha ,\gamma$