Radius of a certain orbit of hydrogen atom is 8.48 A ~ … . If energy of electron in this orbit is E / x . then x = _____ (Given a 0 = 0.529 A ~ … , E = energy of electron in ground state).

We know r = 0.529 Z n 2 ⇒ 8.48 = 0.529 1 n 2 n 2 = 16 ⇒ n = 4 We know E ∝ n 2 1 E n th = 16 E x = 16

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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2024

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Radius of a certain orbit of hydrogen atom is $8.48 \tilde{A} \dots$ . If energy of electron in this orbit is $E / x$ . then $x =$ _____ (Given $a_{0} = 0.529 \tilde{A} \dots, E =$ energy of electron in ground state).

Answer:

16.00

Solution:

We know $r = 0.529 \frac{n ^{2}}{Z} \Rightarrow 8.48 = 0.529 \frac{n ^{2}}{1} n^{2} = 16 \Rightarrow n = 4$
We know $E \propto \frac{1}{n ^{2}}$ $E_{n^{th}} = \frac{E}{16} x = 16$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2024

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