Physics - Modern Physics Question with Solution | TestHub

According to Einstein's photoelectric equation, the maximum kinetic energy of emitted photoelectrons is given by:

$K_{\text{max}}=hv-h{v}_0$

The maximum kinetic energy is also related to the stopping potential $V_s$ by the equation:

$K_{\text{max}}=e{V}_s$

Equating the two expressions, we get:

$e{V}_s=hv-h{v}_0$

$V_s=\frac{h}{e}v-\frac{h}{e}{v}_0$

From this relation, it is clear that the stopping potential $V_s$ is directly proportional to the frequency of the incident radiation $v$. Therefore, if the frequency of incident radiation is increased, the stopping potential increases.

Answer: increases