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PhysicsModern PhysicsNuclear physicsEasy2 minPYQ_2024

PhysicsEasynumerical

A nucleus has mass number $A_{1}$ and volume $V_{1}$ . Another nucleus has mass number $A_{2}$ and volume $V_{2}$ . If relation between mass number is $A_{2} = 4 A_{1}$ , then $\frac{V_{2}}{V_{1}} =$ _______.

Answer:

4.00

Solution:

For a nucleus we can write volume: $V = \frac{4}{3} π R^{3}$

Now, $R = R_{0} {(A)}^{\frac{1}{3}}$

Therefore, $V = \frac{4}{3} π R_{0}^{3} A$

$\Rightarrow \frac{V_{2}}{V_{1}} = \frac{A_{2}}{A_{1}} = 4$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2024

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