Physics - Modern Physics Question with Solution | TestHub

$\mathrm{E}={\mathrm{mC}}^2$ $\begin{array}{rl}& \Rightarrow \mathrm{E}=\left(1\times 10^{-3}\right)\times {\left(3\times 10^8\right)}^2\mathrm{J}\\ & \Rightarrow \mathrm{E}=\left(10^{-3}\right)\left(9\times 10^{16}\right)\left(6.241\times 10^{18}\right)\mathrm{eV}\\ & \mathrm{E}=56.169\times 10^{31}\mathrm{eV}\\ & \mathrm{E}\approx 5.6\times 10^{26}\mathrm{MeV}\\ & \end{array}$