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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2024

PhysicsEasynumerical

An electron of hydrogen atom on an excited state is having energy $E_{n} = - 0.85 eV$ . The maximum number of allowed transitions to lower energy level is _______.

Answer:

6.00

Solution:

Energy of $n^{t h}$ orbit is given by, $E_{n} = - \frac{13.6}{n^{2}}$

$\Rightarrow - \frac{13.6}{n^{2}} = - 0.85 \Rightarrow n = 4$

No of transition,

$= \frac{n (n - 1)}{2} = \frac{4 (4 - 1)}{2} = 6$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2024

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