Physics - Modern Physics Question with Solution | TestHub

$h\frac{c}{{\lambda }_1}=\frac{-5E}{2}+4E=\frac{3}{2}E$...(i) $h\frac{c}{{\lambda }_2}=-2E+3E=E$...(ii) $h\frac{C}{{\lambda }_3}=-2E+4E=2E$...(iii) Comparing (2) and (3) $\frac{1}{{\lambda }_3}=\frac{2}{{\lambda }_2}{\lambda }_2=2{\lambda }_3$ Comparing (1) and (2) $3{\lambda }_1=2{\lambda }_2{\lambda }_1<{\lambda }_2$