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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2023

PhysicsMediumsingle choice

The de Broglie wavelength associated with an electron, accelerated by a potential difference of $81 V$ is given by:NEET 2023 (Manipur)

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Solution:

We know, for an electron De Broglie wavelength, $λ = \frac{12.27}{v} \overset{˚}{A}$ $λ = \frac{12.27}{81} = \frac{12.27}{9} \overset{˚}{A} λ = 1.36 \overset{˚}{A} or 0.136 nm$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2023

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