A nucleus with mass number 242 and binding energy per nucleon as 7 . 6 MeV breaks into two fragment each with mass number 121 . If each fragment nucleus has binding energy per nucleon as 8 . 1 MeV , t

Question

A nucleus with mass number 242 and binding energy per nucleon as 7 . 6 MeV breaks into two fragment each with mass number 121 . If each fragment nucleus has binding energy per nucleon as 8 . 1 MeV , the total gain in binding energy is _ _ _ _ _ _ _ MeV .

TestHub · Accepted Answer

Binding energy is given by E = ∆ m c 2 where ∆ m is the mass defect. The energy per nucleon of the nucleus having mass number 242 is 7 . 6 MeV . The initial binding energy is, B E = 242 × 7 . 6 MeV The energy per nucleon of the nucleus with mass number 121 is 8 . 1 MeV . Therefore, binding energy is B E ' = 2 121 × 8 . 1 MeV The gain in the binding energy is B E ' - B E = ( 8 . 1 – 7 . 6 ) × 242 MeV = 121 MeV = 121 MeV

Physics - Modern Physics Question with Solution | TestHub

Doubts & Discussion