The variation of stopping potential V 0 as a function of the frequency ( ν ) of the incident light for a metal is shown in figure. The work function of the surface is

Question

TestHub · Accepted Answer

The relation between the stopping potential and the frequency of the incident light is given by
$e V_{0} = h ν - ϕ . . . (1)$
When $V_{0} = 0$ ,
$ϕ = h ν . . . (2)$
Substitute the value of the frequency corresponding to zero stopping potential into equation (2) to calculate the required work function of the material.
$\begin{array}{rcl} ϕ & = & \frac{6.626 \times 10^{- 34} J \cdot s \times 5 \times 10^{14} Hz}{1.6 \times 10^{- 19} J / eV} \\ = & \frac{6.626 \times 5}{16} \approx 2.07 eV \end{array}$

Physics - Modern Physics Question with Solution | TestHub

Options:

Doubts & Discussion