Physics - Modern Physics Question with Solution | TestHub

For Paschen series, Longest wavelength corresponds to $\begin{array}{rl}& {\mathrm{n}}_1=3,{\mathrm{n}}_2={\mathrm{n}}_1+1=4\\ & {\lambda }_{\max }=\frac{144}{7\mathrm{R}}\end{array}$ Shortest wavelength corresponds to ${\mathrm{n}}_1=3,{\mathrm{n}}_2=\infty$ $\begin{array}{rl}{\lambda }_{\min }& =\frac{9}{R}\\ \therefore & \frac{{\lambda }_{\max }}{{\lambda }_{\min }}=\frac{\left(\frac{144}{7R}\right)}{\left(\frac{9}{R}\right)}=\frac{144}{63}\end{array}$