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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2022
PhysicsMediumsingle choice

Given below are two statements

Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit E1 to higher energy orbit E2, is given as hf=E1-E2

Statement II: The jumping of electron from higher energy orbit E2 to lower energy orbit E1 is associated with frequency of radiation given as f=E2-E1h. This condition is Bohr's frequency condition.

In the light of the above statements, choose the correct answer from the options given below:

Question diagram: Given below are two statements Statement I: In hydrogen atom

Options:

Answer:
D
Solution:

 

According to Bohr's model, when electron makes the transition from lower orbit to higher orbit, its energy can be given as

 E=Efinal-Einitial=hf, here, h is Planck's constant.

Then, f=E2-E1h.

Bohr's frequency condition is the law that state that the frequency of the radiation emitted or absorbed during the transition of an atomic system between two stationary states equals the difference in the energies of the states divided by Planck's constant.

Hence, Statement I is incorrect but statement II is true.

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure
2mℹ️ Source: PYQ_2022

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