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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2021

PhysicsEasystatement

The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength $491 nm$ is $0.710 V .$ When the incident wavelength is changed to a new value, the stopping potential is $1.43 V .$ The new wavelength is :

Options:

Answer:

Solution:

$\frac{h c}{λ} = ϕ + e V_{s}$

$\frac{1240}{491} = ϕ + 0.71 . . . (1)$

$\frac{1240}{λ} = ϕ + 1.43 . . . (2)$

$∴ λ = 382 nm$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2021

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