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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2021

PhysicsEasystatement

An electron of mass $m$ and a photon have same energy $E .$ The ratio of wavelength of electron to that of photon is : ( $c$ being the velocity of light)

Options:

Answer:

Solution:

$λ_{1} = \frac{h}{\sqrt{2 m E}}$

$λ_{2} = \frac{h c}{E}$

$\frac{λ_{1}}{λ_{2}} = \frac{1}{c} {(\frac{E}{2 m})}^{1 / 2}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2021

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