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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2021

PhysicsMediumstatement

An electron of mass $m_{e}$ and a proton of mass $m_{p} = 1836 m_{e}$ are moving with the same speed. The ratio of their de Broglie wavelength $\frac{λ_{e l e c t r o n}}{λ_{p r o t o n}}$ will be :

Options:

Answer:

Solution:

Given mass of electron $= m_{e}$
Mass of proton $= m_{p}$
$∴$ given $m_{p} = 1836 m_{e}$
From de-Broglie wavelength
$λ = \frac{h}{p} = \frac{h}{mv}$
$\frac{λ_{e}}{λ_{p}} = \frac{m_{p}}{m_{e}}$
$= \frac{1836 m_{e}}{m_{e}}$
$\frac{λ_{e}}{λ_{p}} = 1836$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2021

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