The temperature of an ideal gas in three dimensions is 300 K . The corresponding de-Broglie wavelength of the electron approximately at 300 K is: m e = mass of electron = 9 × 10 - 31 kg , h = Planck c

Question

The temperature of an ideal gas in three dimensions is $300 K .$ The corresponding de-Broglie wavelength of the electron approximately at $300 K$ is:

$[m_{e} =$ mass of electron $= 9 \times 10^{- 31} kg$ , $h =$ Planck constant $= 6.6 \times 10^{- 34} J s$ , $k_{B} =$ Boltzmann constant $= 1.38 \times 10^{- 23} J K^{- 1}]$

TestHub · Accepted Answer

k = 1 . 38 × 10 - 23 J K - 1 Mass of electron = 9 × 10 - 31 kg ⇒ λ D = h 2 m × 3 2 × k T = h 3 mkT ⇒ λ D = 6 . 6 × 10 - 34 3 × 9 × 10 - 31 × 1 . 38 × 10 - 23 × 300 = 6 . 6 × 10 - 34 105 . 72 × 10 - 27 = 62 A ο Thus x = 62 A ο

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