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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

Photons of energy 1 eV and 2.5 eV successively illuminated a metal whose work function is 0.5 eV. The ratio of maximum speeds of emitted electron is

Options:

Answer:

Solution:

Energy of photon $E = ϕ + \frac{1}{2} m v^{2}$

$V_{\max} = \sqrt{\frac{2 (E - ϕ)}{m}}$

So putting values

$\frac{V_{\max 1}}{V_{m a x 2}} = \sqrt{\frac{1 - 0.5}{2.5 - 0.5}}$

$\frac{V_{\max 1}}{V_{\max 2}} = \frac{1}{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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