Physics - Modern Physics Question with Solution | TestHub

Number of fissions that can occur in$\mathrm{1 }\mathrm{kg}$of$U^{235}$is$n_1=\frac{N_A}{235 \left(kg\right)} :N_A$is the Avogadro number.

Number of fusions that can occur for$\mathrm{1 }\mathrm{kg}$of hydrogen is$n_2=\frac{N_A/\left(1 kg\right)}{4}$, because$4$hydrogen nuclei fuse to form one helium nuclei.

$\frac{E_2}{E_1}=\frac{n_2\times 24.7 MeV}{n_1\times 200MeV}=\frac{235\times 24.7}{4\times 200}=7.25$(approx)

$=7$