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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2020

PhysicsEasysingle choice

An electron is accelerated under a potential difference of $64 V,$ the de-Broglie wavelength associated with electron is $[e = - 1.6 \times 10^{- 19} C$ , $m_{e} = 9.1 \times 10^{- 31} kg$ , $h = 6 .623 \times 10^{- 34} Js]$

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Answer:

Solution:

Modified equation of de-Broglie wavelength $λ = \frac{h}{\sqrt{2 m e V}}$
$λ = \frac{12.27 \overset{o}{A}}{\sqrt{V}} = \frac{12.27}{\sqrt{64}} = 1.534 \overset{o}{A}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2020

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