Physics - Modern Physics Question with Solution | TestHub

Decrease in mass number due to emission of$3\mathrm{\alpha }$-particles

and a$\mathrm{\beta }-\mathrm{p}\mathrm{a}\mathrm{r}\mathrm{t}\mathrm{i}\mathrm{c}\mathrm{l}\mathrm{e}=3\times 4=12$

Decrease in charge number in the process

$=3\times 2-1=5$

$\therefore$For the resulting element,

$A=228-12=216$

$Z=88-5=83$