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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020

PhysicsEasysingle choice

For a radioactive sample, the initial activity of the material was $8$ $cps$ and after $3 h$ it becomes $1$ $cps$ . The half-life of the sample is

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Answer:

Solution:

Here $A_{0} = 8$ counts, $A =$ $1$ count and $t = 3 h$ .

$\frac{A}{A_{0}} = {(\frac{1}{2})}^{n}$

$\Rightarrow \frac{1}{8} = {(\frac{1}{2})}^{n}$

or ${(\frac{1}{2})}^{3} = {(\frac{1}{2})}^{n} \Rightarrow n = 3$

So, $T_{1 / 2} = \frac{t}{n} = \frac{3}{3} = 1 h$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2020

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