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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

When a electron jumps from a higher energy state to a lower energy state with an energy difference of $Δ E$ electron-volt, then the wavelength of the spectral line emitted is approximately

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Answer:

Solution:

Energy, $h v = Δ E$ electron volt.

$\Rightarrow \frac{h c}{λ} = Δ E$ electron volt.

$\Rightarrow λ = \frac{h c}{Δ E} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{Δ E}$

But, $1 e V = 16 \times 10^{- 19} J$

$∴ λ = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{Δ E \times 16 \times 10^{- 19}} m$

$\Rightarrow λ = \frac{12375 \times 10^{- 10}}{Δ E} m$

$\Rightarrow λ = \frac{12375}{Δ E} Å$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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