Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2020

PhysicsEasystatement

A particle moving with kinetic energy $E$ has de Broglie wavelength $λ$ . If energy $Δ E$ is added to its energy, the wavelength become $\frac{λ}{2}$ . Value of $Δ E,$ is:

Options:

Answer:

Solution:

$λ = \frac{h}{\sqrt{2 (K E) m}} \Rightarrow λ \propto \frac{1}{\sqrt{K E}}$
$\frac{λ}{\frac{λ}{2}} = \sqrt{\frac{K E_{f}}{K E_{i}}}$
$4 K E_{i} = K E_{f}$
$\Rightarrow Δ E = 4 K E_{i} - K E_{i} = 3 K E = 3 E$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...