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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

The difference between kinetic energies of photoelectrons emitted from a surface by the light of wavelength $2500 \overset{\circ}{A}$ and $5000 \overset{\circ}{A}$ will be

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Answer:

Solution:

$Δ E = \frac{h c}{λ_{1}} - \frac{h c}{λ_{2}} = \frac{h c (λ_{2} - λ_{1})}{λ_{1} λ_{2}} (i n e V)$

$= \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8} \times (5000 - 2500) \times 10^{- 10}}{2500 \times 5000 \times 10^{- 20} \times 1.6 \times 10^{- 19}}$

$= 2.47 e V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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