In the photoelectric effect, the maximum speed of electrons is found to be 6 × 10 5 m s - 1 . The wavelength used is 4000 Å . The work function of the metal is

hc λ = KE Max + ϕ 12400 4000 = 1 2 × 9 .1 × 10 - 31 × 36 × 10 10 1 .6 × 10 - 19 + ϕ 3.1 = 102.375 × 10 - 2 + ϕ ϕ = 2.076 eV

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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

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In the photoelectric effect, the maximum speed of electrons is found to be $6 \times 10^{5} m s^{- 1}$ . The wavelength used is $4000 Å$ . The work function of the metal is

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Answer:

Solution:

$\frac{hc}{λ} = {(KE)}_{Max} + ϕ$

$\frac{12400}{4000} = \frac{\frac{1}{2} \times 9 .1 \times 10^{- 31} \times 36 \times 10^{10}}{1 .6 \times 10^{- 19}} + ϕ$

$3.1 = 102.375 \times 10^{- 2} + ϕ$

$ϕ = 2.076 eV$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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