Imagine that a reactor converts all the given mass into energy and that it operates at a power level of $10^{9}$ watt. The mass of the fuel consumed per hour, in the reactor, will be
(velocity of light, $c$ is $3 \times 10^{8} m s^{- 1}$ )

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TestHub · Accepted Answer

P = E Δ t = Δ m c 2 Δ t ∆ m ∆ t = P c 2 = 10 9 3 × 10 8 2 ⇒ ∆ m ∆ t = 10 - 7 9 k g s - 1 = 10 - 7 9 × 1000 g 3600 h - 1 = 4 × 10 - 2 g h - 1

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