Physics - Modern Physics Question with Solution | TestHub

$\lambda =\frac{h}{\sqrt{2\mathit{\text{mq}}V}}$

${\left(10^{-13}\right)}^2=\frac{{\left(6\text{.}6\times 10^{-34}\right)}^2}{2\times 1\text{.}67\times 10^{27}\times 1\text{.}6\times 10^{-19}V}$

$V=8\text{.}2\times 10^4\text{volt}$