A beam of light of intensity I is normally incident on a plate of area A . If plate absorbs fraction η of incident light and reflects rest of it back, then the force exerted by the incident light on t

Question

A beam of light of intensity I is normally incident on a plate of area A . If plate absorbs fraction η of incident light and reflects rest of it back, then the force exerted by the incident light on the plate is given by [ c =speed of light]

TestHub · Accepted Answer

Force exerted by the fraction of ,ight that is absorbed is given as, $F_{1} = \frac{ηIA}{c}$ .

Force exerted by the fraction of light that is totally reflected is given as, $F_{2} = \frac{(1 - η) \times 2 IA}{c}$ .

Hence, total force will be given as, $F = F_{1} + F_{2} = \frac{(2 - η) IA}{c}$ .

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