A particle moving with a velocity 1 10 t h of that of light will cross a nucleus in about

t = 2 r v = 2 × 1 0 – 15 m 3 × 1 0 7 m s - 1 = 2 3 × 1 0 – 22 s

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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

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A particle moving with a velocity ${\frac{1}{10}}^{t h}$ of that of light will cross a nucleus in about

Answer:

Solution:

$t = \frac{2 r}{v} = \frac{2 \times 1 0^{- 15} m}{3 \times 1 0^{7} m s^{- 1}} = \frac{2}{3} \times 1 0^{- 22} s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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